tag:blogger.com,1999:blog-8188980643300007683.post4385710150672899605..comments2023-05-08T01:07:35.723-07:00Comments on Steve's maths: Simultaneous equationsUnknownnoreply@blogger.comBlogger1125tag:blogger.com,1999:blog-8188980643300007683.post-21985335494720190892009-09-30T11:26:05.732-07:002009-09-30T11:26:05.732-07:00Steve this how i done it but still something is wr...Steve this how i done it but still something is wrong when <br />6(2x - 3) = 42 <br /> I divide both sides by 6:(2x - 3) = 7 <br /> I lose the brackets add 3 to both sides so the answers must be 2x=9 with calcultor it give me 2x=10 to make 10 where did the other number that makes 10 come from ? I have no idea <br /><br />NadarNadarhttps://www.blogger.com/profile/16839384344282563955noreply@blogger.com